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Question 188 - 200-201 discussion

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Which regular expression is needed to capture the IP address 192.168.20.232?

A.

^ (?:[0-9]{1,3}\.){3}[0-9]{1,3}

Answers
A.

^ (?:[0-9]{1,3}\.){3}[0-9]{1,3}

B.

^ (?:[0-9]f1,3}\.){1,4}

Answers
B.

^ (?:[0-9]f1,3}\.){1,4}

C.

^ (?:[0-9]{1,3}\.)'

Answers
C.

^ (?:[0-9]{1,3}\.)'

D.

^ ([0-9]-{3})

Answers
D.

^ ([0-9]-{3})

Suggested answer: A

Explanation:

The regular expression ^ (?:[0-9]{1,3}.){3}[0-9]{1,3} is needed to capture the IP address 192.168.20.232. This regex matches any string that starts with three groups of one to three digits followed by a dot, and ends with one group of one to three digits. The IP address 192.168.20.232 matches this pattern exactly. The other options are either invalid or do not match the IP address format.Reference:= Cisco Cybersecurity Operations Fundamentals, Module 5: Security Policies and Procedures, Lesson 5.3: Data and Event Analysis, Topic 5.3.2: Regular Expressions

asked 07/10/2024
Kamran Kamran
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