ExamGecko

212-81: Certified Encryption Specialist

Certified Encryption Specialist
Vendor:

ECCouncil

Certified Encryption Specialist Exam Questions: 206
Certified Encryption Specialist   2.370 Learners
Take Practice Tests
Comming soon
PDF | VPLUS

The EC-Council 212-81 exam is a key certification for professionals specializing in Certified Encryption Specialist (E|CES). Our comprehensive resource for 212-81 practice tests, shared by individuals who have successfully passed the exam, provides realistic scenarios and invaluable insights to enhance your exam preparation.

Why Use 212-81 Practice Test?

  • Real Exam Experience: Our practice test accurately replicates the format and difficulty of the actual EC-Council 212-81 exam, providing you with a realistic preparation experience.

  • Identify Knowledge Gaps: Practicing with these tests helps you identify areas where you need more study, allowing you to focus your efforts effectively.

  • Boost Confidence: Regular practice with exam-like questions builds your confidence and reduces test anxiety.

  • Track Your Progress: Monitor your performance over time to see your improvement and adjust your study plan accordingly.

Key Features of 212-81 Practice Test:

  • Up-to-Date Content: Our community ensures that the questions are regularly updated to reflect the latest exam objectives and technology trends.

  • Detailed Explanations: Each question comes with detailed explanations, helping you understand the correct answers and learn from any mistakes.

  • Comprehensive Coverage: The practice test covers all key topics of the EC-Council 212-81 exam, including cryptography, symmetric and asymmetric encryption, and cryptanalysis.

  • Customizable Practice: Create your own practice sessions based on specific topics or difficulty levels to tailor your study experience to your needs.

Exam number: 212-81

Exam name: Certified Encryption Specialist (E|CES 212-81)

Length of test: 120 minutes

Exam format: Multiple-choice questions

Exam language: English

Number of questions in the actual exam: 50 questions

Passing score: 70%

Use the member-shared EC-Council 212-81 Practice Test to ensure you’re fully prepared for your certification exam. Start practicing today and take a significant step towards achieving your certification goals!

Related questions

Message hidden in unrelated text. Sender and receiver have pre-arranged to use a pattern to remove certain letters from the message which leaves only the true message behind.

A.
Caesar Cipher
A.
Caesar Cipher
Answers
B.
Null Ciphers
B.
Null Ciphers
Answers
C.
Vigenere Cipher
C.
Vigenere Cipher
Answers
D.
Playfair Cipher
D.
Playfair Cipher
Answers
Suggested answer: B

Explanation:

Null Ciphers

https://en.wikipedia.org/wiki/Null_cipher

A null cipher, also known as concealment cipher, is an ancient form of encryption where the plaintext is mixed with a large amount of non-cipher material. Today it is regarded as a simple form of steganography, which can be used to hide ciphertext.

Incorrect answers:

Caesar Cipher - Monoalphabetic cipher where letters are shifted one or more letters in either direction. The method is named after Julius Caesar, who used it in his private correspondence.

Vigenre - method of encrypting alphabetic text by using a series of interwoven Caesar ciphers, based on the letters of a keyword. It employs a form of polyalphabetic substitution.

Playfair Cipher - manual symmetric encryption technique and was the first literal digram substitution cipher. The scheme was invented in 1854 by Charles Wheatstone, but bears the name of Lord Playfair for promoting its use.

asked 18/09/2024
Wojciech Romaldowski
43 questions

Ahlen is using a set of pre-calculated hashes to attempt to derive the passwords from a Windows SAM file. What is a set of pre-calculated hashes used to derive a hashed password called?

Become a Premium Member for full access
Unlock Premium Member  Unlock Premium Member

The most common way steganography is accomplished is via which one of the following?

A.
rsb
A.
rsb
Answers
B.
Isb
B.
Isb
Answers
C.
msb
C.
msb
Answers
D.
asb
D.
asb
Answers
Suggested answer: B

Explanation:

lbs

https://en.wikipedia.org/wiki/Bit_numbering#:~:text=In%20computing%2C%20the%20least%20significant,number%20is%20even%20or%20odd.

The least significant bit (LSB) is the bit position in a binary integer giving the units value, that is, determining whether the number is even or odd. The LSB is sometimes referred to as the low-order bit or right-most bit, due to the convention in positional notation of writing less significant digits further to the right. It is analogous to the least significant digit of a decimal integer, which is the digit in the ones (right-most) position.

asked 18/09/2024
Akash Makkar
35 questions

Represents the total number of possible values of keys in a cryptographic algorithm or other security measure, such as a password.

Become a Premium Member for full access
Unlock Premium Member  Unlock Premium Member

With Cipher-block chaining (CBC) what happens?

A.
The block cipher is turned into a stream cipher
A.
The block cipher is turned into a stream cipher
Answers
B.
The message is divided into blocks and each block is encrypted separately. This is the most basic mode for symmetric encryption
B.
The message is divided into blocks and each block is encrypted separately. This is the most basic mode for symmetric encryption
Answers
C.
Each block of plaintext is XORed with the previous ciphertext block before being encrypted
C.
Each block of plaintext is XORed with the previous ciphertext block before being encrypted
Answers
D.
The cipher text from the current round is XORed with the plaintext for the next round
D.
The cipher text from the current round is XORed with the plaintext for the next round
Answers
Suggested answer: C

Explanation:

Each block of plaintext is XORed with the previous ciphertext block before being encrypted

https://en.wikipedia.org/wiki/Block_cipher_mode_of_operation#Cipher_block_chaining_(CBC)

In CBC mode, each block of plaintext is XORed with the previous ciphertext block before being encrypted. This way, each ciphertext block depends on all plaintext blocks processed up to that point. To make each message unique, an initialization vector must be used in the first block.

asked 18/09/2024
Casie Clements
37 questions

In 2007, this wireless security algorithm was rendered useless by capturing packets and discovering the passkey in a matter of seconds. This security flaw led to a network invasion of TJ Maxx and data theft through a technique known as wardriving.

Which Algorithm is this referring to?

Become a Premium Member for full access
Unlock Premium Member  Unlock Premium Member

Nicholas is working at a bank in Germany. He is looking at German standards for pseudo random number generators. He wants a good PRNG for generating symmetric keys. The German Federal Office for Information Security (BSI) has established four criteria for quality of random number generators. Which ones can be used for cryptography?

A.
K4
A.
K4
Answers
B.
K5
B.
K5
Answers
C.
K3
C.
K3
Answers
D.
K2
D.
K2
Answers
E.
K1
E.
K1
Answers
Suggested answer: A, C

Explanation:

K3 and K4

https://en.wikipedia.org/wiki/Pseudorandom_number_generator

The German Federal Office for Information Security (Bundesamt fr Sicherheit in der Informationstechnik, BSI) has established four criteria for quality of deterministic random number generators.They are summarized here:

K1 -- There should be a high probability that generated sequences of random numbers are different from each other.

K2 -- A sequence of numbers is indistinguishable from 'truly random' numbers according to specified statistical tests. The tests are the monobit test (equal numbers of ones and zeros in the sequence), poker test (a special instance of the chi-squared test), runs test (counts the frequency of runs of various lengths), longruns test (checks whether there exists any run of length 34 or greater in 20 000 bits of the sequence)---both from BSI and NIST, and the autocorrelation test. In essence, these requirements are a test of how well a bit sequence: has zeros and ones equally often; after a sequence of n zeros (or ones), the next bit a one (or zero) with probability one-half; and any selected subsequence contains no information about the next element(s) in the sequence.

K3 -- It should be impossible for an attacker (for all practical purposes) to calculate, or otherwise guess, from any given subsequence, any previous or future values in the sequence, nor any inner state of the generator.

K4 -- It should be impossible, for all practical purposes, for an attacker to calculate, or guess from an inner state of the generator, any previous numbers in the sequence or any previous inner generator states.

For cryptographic applications, only generators meeting the K3 or K4 standards are acceptable.

asked 18/09/2024
james campbell
38 questions

If Bob is using asymmetric cryptography and wants to send a message to Alice so that only she can decrypt it, what key should he use to encrypt the message?

A.
Alice's private key
A.
Alice's private key
Answers
B.
Bob's private key
B.
Bob's private key
Answers
C.
Alice's public key
C.
Alice's public key
Answers
D.
Bob's public key
D.
Bob's public key
Answers
Suggested answer: C

Explanation:

Alice's public key

https://en.wikipedia.org/wiki/Diffie%E2%80%93Hellman_key_exchange

In asymmetric (public key) cryptography, both communicating parties (i.e. both Alice and Bob) have two keys of their own --- just to be clear, that's four keys total. Each party has their own public key, which they share with the world, and their own private key which they ... well, which they keep private, of course but, more than that, which they keep as a closely guarded secret. The magic of public key cryptography is that a message encrypted with the public key can only be decrypted with the private key. Alice will encrypt her message with Bob's public key, and even though Eve knows she used Bob's public key, and even though Eve knows Bob's public key herself, she is unable to decrypt the message. Only Bob, using his secret key, can decrypt the message ... assuming he's kept it secret, of course.

asked 18/09/2024
Rodrigo Serrano dos Santos
38 questions

John is going to use RSA to encrypt a message to Joan. What key should he use?

A.
A random key
A.
A random key
Answers
B.
Joan's public key
B.
Joan's public key
Answers
C.
A shared key
C.
A shared key
Answers
D.
Joan's private key
D.
Joan's private key
Answers
Suggested answer: B

Explanation:

Joan's public key

https://en.wikipedia.org/wiki/RSA_(cryptosystem)

Suppose Joahn uses Bob's public key to send him an encrypted message. In the message, she can claim to be Alice but Bob has no way of verifying that the message was actually from Alice since anyone can use Bob's public key to send him encrypted messages. In order to verify the origin of a message, RSA can also be used to sign a message.

Suppose Alice wishes to send a signed message to Bob. She can use her own private key to do so. She produces a hash value of the message, raises it to the power of d (modulo n) (as she does when decrypting a message), and attaches it as a 'signature' to the message. When Bob receives the signed message, he uses the same hash algorithm in conjunction with Alice's public key. He raises the signature to the power of e (modulo n) (as he does when encrypting a message), and compares the resulting hash value with the message's actual hash value. If the two agree, he knows that the author of the message was in possession of Alice's private key, and that the message has not been tampered with since.

asked 18/09/2024
sheldan simeina
36 questions

3DES can best be classified as which one of the following?

Become a Premium Member for full access
Unlock Premium Member  Unlock Premium Member