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Question 235 - 200-201 discussion

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Refer to the exhibit.

What must be interpreted from this packet capture?

A.

IP address 192.168.88 12 is communicating with 192 168 88 149 with a source port 74 to destination port 49098 using TCP protocol

Answers
A.

IP address 192.168.88 12 is communicating with 192 168 88 149 with a source port 74 to destination port 49098 using TCP protocol

B.

IP address 192.168.88.12 is communicating with 192 168 88 149 with a source port 49098 to destination port 80 using TCP protocol.

Answers
B.

IP address 192.168.88.12 is communicating with 192 168 88 149 with a source port 49098 to destination port 80 using TCP protocol.

C.

IP address 192.168.88.149 is communicating with 192.168 88.12 with a source port 80 to destination port 49098 using TCP protocol.

Answers
C.

IP address 192.168.88.149 is communicating with 192.168 88.12 with a source port 80 to destination port 49098 using TCP protocol.

D.

IP address 192.168.88.149 is communicating with 192.168.88.12 with a source port 49098 to destination port 80 using TCP protocol.

Answers
D.

IP address 192.168.88.149 is communicating with 192.168.88.12 with a source port 49098 to destination port 80 using TCP protocol.

Suggested answer: C

Explanation:

The packet capture shows that IP address 192.168.88.149, using source port 80 (common for HTTP traffic), initiated communication with IP address 192.168.88.12 at destination port 49098, using the TCP protocol, indicating a typical client-server interaction over the web.

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asked 07/10/2024
Vinayaka G D
39 questions
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