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Question 62 - 300-410 discussion

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Refer to the exhibit.

Redistribution is enabled between the routing protocols, and nowPC2 PC3, and PC4 cannot reach PC1. What are the two solutions to fix the problem? (Choose two.)

A.

Filter RIP routes back into RIP when redistributing into RIP in R2

Answers
A.

Filter RIP routes back into RIP when redistributing into RIP in R2

B.

Filter OSPF routes into RIP FROM EIGRP when redistributing into RIP in R2.

Answers
B.

Filter OSPF routes into RIP FROM EIGRP when redistributing into RIP in R2.

C.

Filter all routes except RIP routes when redistributing into EIGRP in R2.

Answers
C.

Filter all routes except RIP routes when redistributing into EIGRP in R2.

D.

Filter RIP AND OSPF routes back into OSPF from EIGRP when redistributing into OSPF in R2

Answers
D.

Filter RIP AND OSPF routes back into OSPF from EIGRP when redistributing into OSPF in R2

E.

Filter all routes except EIGRP routes when redistributing into OSPF in R3.

Answers
E.

Filter all routes except EIGRP routes when redistributing into OSPF in R3.

Suggested answer: A, C

Explanation:

Even PC2 cannot reach PC1 so there is something wrong with RIP redistribution in R2. Because RIP has higher Administrative Distance (AD) value than OSPF and EIGRP so it will be looped when doing mutual redistribution.

asked 07/10/2024
Leonardo Amorim
32 questions
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