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Question 1

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Refer to the code below: 01 const exec = (item, delay) =>{ 02 new Promise(resolve => setTimeout( () => resolve(item), delay)), 03 async function runParallel() { 04 Const (result1, resul

Question 2

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A developer needs to test this function: 01 const sum3 = (arr) => ( 02 if (!arr.length) return 0, 03 if (arr.length === 1) return arr[0], 04 if (arr.length === 2) return arr[0] + arr[1], 05

Question 3

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Which statement phrases successfully?

Question 4

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Refer to the code below: 01 let car1 = new promise((_, reject) => 02 setTimeout(reject, 2000, "Car 1 crashed in")); 03 let car2 = new Promise(resolve => setTimeout(resolve, 1500, "Car 2 com

Question 5

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Refer to the code below: for(let number =2 ; number <= 5 ; number += 1 ) { // insert code statement here } The developer needs to insert a code statement in the location shown. The code statem

Question 6

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A developer is working on an ecommerce website where the delivery date is dynamically calculated based on the current day. The code line below is responsible for this calculation. Const deliveryDat

Question 7

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Which three statements are true about promises ? Choose 3 answers

Question 8

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Given the code below: 01 function GameConsole (name) { 02 this.name = name; 03 } 04 05 GameConsole.prototype.load = function(gamename) { 06 console.log( ` $(this.name) is loading a game : $(ga

Question 9

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A developer has the following array of student test grades: Let arr = [ 7, 8, 5, 8, 9 ]; The Teacher wants to double each score and then see an array of the students who scored more than 15 points

Question 10

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A test has a dependency on database.query. During the test the dependency is replaced with an object called database with the method, query, that returns an array. The developer needs to verify how

Question 212 - Certified JavaScript Developer I discussion

Refer to the code below

let inArray = [[1,2],[3,4,5]];

which two statements results in the array [1,2,3,4,5]?

choose 2 answer

A.

[ ].concat(...inArray);

B.

[ ].concat.apply(inArray,[ ]);

C.

[ ].concat([...inArray])

D.

[ ].concat.apply([ ],inArray);

Show Answer

asked 23/09/2024

Subha Mishra

39 questions

Your answer: A B C D

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