ExamGecko
Question list
Search
Search

List of questions

Search

Related questions











Question 67 - Certified MuleSoft Integration Architect I discussion

Report
Export

Refer to the exhibit.

An organization is sizing an Anypoint VPC for the non-production deployments of those Mule applications that connect to the organization's on-premises systems. This applies to approx. 60 Mule applications. Each application is deployed to two CloudHub i workers. The organization currently has three non-production environments (DEV, SIT and UAT) that share this VPC. The AWS region of the VPC has two AZs.

The organization has a very mature DevOps approach which automatically progresses each application through all non-production environments before automatically deploying to production. This process results in several Mule application deployments per hour, using CloudHub's normal zero-downtime deployment feature.

What is a CIDR block for this VPC that results in the smallest usable private IP address range?

A.
10.0.0.0/26 (64 IPS)
Answers
A.
10.0.0.0/26 (64 IPS)
B.
10.0.0.0/25 (128 IPs)
Answers
B.
10.0.0.0/25 (128 IPs)
C.
10.0.0.0/24 (256 IPs)
Answers
C.
10.0.0.0/24 (256 IPs)
D.
10.0.0.0/22 (1024 IPs)
Answers
D.
10.0.0.0/22 (1024 IPs)
Suggested answer: D

Explanation:

Mule applications are deployed in CloudHub workers and each worker is assigned with a dedicated IP * For zero downtime deployment, each worker in CloudHub needs additional IP addresses * A few IPs in a VPC are reserved for infrastructure (generally 2 IPs) * The IP addresses are usually in a private range with a subnet block specifier, such as 10.0.0.1/24 * The smallest CIDR network subnet block you can assign for your VPC is /24 (256 IP addresses) (60*3 env * 2 worker per application ) + 50% of (total) for zero downtime = 540 In this case correct answer is 10.0.0.0/22 as this provided 1024 IP's .

Other IP's are insufficient.

asked 23/09/2024
paloma giraudo
34 questions
User
Your answer:
0 comments
Sorted by

Leave a comment first