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Question 137 - COF-C02 discussion

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Which Snowflake function will interpret an input string as a JSON document, and produce a VARIANT value?

A.
parse_json()
Answers
A.
parse_json()
B.
json_extract_path_text()
Answers
B.
json_extract_path_text()
C.
object_construct()
Answers
C.
object_construct()
D.
flatten
Answers
D.
flatten
Suggested answer: A

Explanation:

Theparse_json()function in Snowflake interprets an input string as a JSON document and produces a VARIANT value containing the JSON document.This function is specifically designed for parsing strings that contain valid JSON information3.

asked 23/09/2024
chalapathy naidu
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