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Question 353 - PT0-002 discussion

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In Java and C/C++, variable initialization is critical because:

A.
the unknown value, when used later, will cause unexpected behavior.
Answers
A.
the unknown value, when used later, will cause unexpected behavior.
B.
the compiler will assign null to the variable, which will cause warnings and errors.
Answers
B.
the compiler will assign null to the variable, which will cause warnings and errors.
C.
the initial state of the variable creates a race condition.
Answers
C.
the initial state of the variable creates a race condition.
D.
the variable will not have an object type assigned to it.
Answers
D.
the variable will not have an object type assigned to it.
Suggested answer: A

Explanation:

Variable initialization is the process of assigning a value to a variable at the time of declaration. In Java and C/C++, variable initialization is critical because if a variable is not initialized, it may contain a garbage value that is unpredictable and may lead to erroneous results or runtime errors when the variable is used later in the program. For example, if a variable is used in a mathematical expression or a conditional statement, the outcome may depend on the value of the variable. If the variable is not initialized, the outcome may be different each time the program is run, or the program may crash due to an invalid operation. Therefore, it is a good practice to always initialize variables before using them, or to check if they have been initialized before using them123.

Reference:

* Different Ways to Initialize a Variable in C++, GeeksforGeeks article by Anshul Aggarwal

* Static variable initialization?, Stack Overflow answer by Pawe Hajdan

* A Guide to Java Initialization, Baeldung article by Eugen Paraschiv

asked 02/10/2024
MIGUEL GAITERO GIL
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