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Question 112 - CWNA-109 discussion

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The BSA of an AP covers the area used by the sales and marketing department. Thirty-five stations operate in this space. The users indicate that they need more throughput and all stations are 5 GHz capable 802.11ac clients. The current AP configuration uses 20 MHz channels in both 2.4 GHz and 5 GHz. What is the least expensive solution available for increasing throughput for these users without implementing configuration options that are not recommended?

A.
Use a 160 MHz channel on the 5 GHz radio
Answers
A.
Use a 160 MHz channel on the 5 GHz radio
B.
Use a 40 MHz channel on the 5 GHz radio
Answers
B.
Use a 40 MHz channel on the 5 GHz radio
C.
Install a second AP in the coverage area
Answers
C.
Install a second AP in the coverage area
D.
Use a 40 MHz channel on the 2.4 GHz radio
Answers
D.
Use a 40 MHz channel on the 2.4 GHz radio
Suggested answer: B

Explanation:

The least expensive solution available for increasing throughput for these users without implementing configuration options that are not recommended is touse a 40 MHz channel on the 5 GHz radio. This solution can double the channel bandwidth and increase the data rates for the 5 GHz capable 802.11ac clients. Using a 40 MHz channel on the 5 GHz radio is also less likely to cause co-channel interference or overlap with other channels than using a 40 MHz channel on the 2.4 GHz radio, which has only three non-overlapping channels. Using a 160 MHz channel on the 5 GHz radio may provide even higher throughput, but it may also consume too much of the available spectrum and cause more interference with other devices or networks. Installing a second AP in the coverage area may also improve the throughput, but it may require additional costs and configuration.Reference:[CWNP Certified Wireless Network Administrator Official Study Guide: Exam CWNA-109], page 216; [CWNA: Certified Wireless Network Administrator Official Study Guide: Exam CWNA-109], page 206.

asked 16/09/2024
Jose Walter
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