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Question 1 - D-PWF-DS-23 discussion

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A customer application generates 2 GB/s writes The outage is under two hours. What capacity must be allowed for the journal?

A.
14.400 GB
Answers
A.
14.400 GB
B.
10.800 GB
Answers
B.
10.800 GB
C.
7,200 GB
Answers
C.
7,200 GB
D.
240 GB
Answers
D.
240 GB
Suggested answer: B

Explanation:

To calculate the required journal capacity, we need to consider the maximum cumulative writes that might occur during an outage. The calculation is based on the application's write bandwidth and the duration of the supported outage. For an application generating 2 GB/s of writes, using a 2-hour outage (which is 7200 seconds), the journal capacity reservation needed is:

JournalCapacity=WriteBandwidthOutageDuration

JournalCapacity=2GB/s7200s=14400GB

However, since the question specifies that the outage is under two hours, we use the minimum outage allowance of 1 hour for the calculation, which is 3600 seconds. Therefore, the correct calculation is:

JournalCapacity=2GB/s3600s=7200GB

But considering the recommendation to use three hours in the calculations for safety, the needed capacity would be approximately 10.547 TB, which is roughly 10.800 GB12. Hence, the verified answer is 10.800 GB.

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asked 16/09/2024
Linda Jannina Sourander
38 questions
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