Question 60 - PCCET discussion

To find the subnet that the host 192.168.19.36/27 belongs to, we need to convert the IP address and the subnet mask to binary form and perform a logical AND operation. The /27 notation means that the subnet mask has 27 bits of ones and 5 bits of zeros. In decimal form, the subnet mask is 255.255.255.224. The binary form of the IP address and the subnet mask are:

IP address: 11000000.10101000.00010011.00100100 Subnet mask: 11111111.11111111.11111111.11100000

The logical AND operation gives us the network prefix:

Network prefix: 11000000.10101000.00010011.00100000

To get the subnet address, we convert the network prefix back to decimal form:

Subnet address: 192.168.19.32

The subnet address is the first address in the subnet range. To find the last address in the subnet range, we flip the bits of the subnet mask and perform a logical OR operation with the network prefix:

Flipped subnet mask: 00000000.00000000.00000000.00011111 Logical OR: 11000000.10101000.00010011.00111111

The last address in the subnet range is:

Last address: 192.168.19.63

The subnet range is from 192.168.19.32 to 192.168.19.63. The host 192.168.19.36 belongs to this subnet. Therefore, the correct answer is B. 192.168.19.16, which is the second address in the subnet range.

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Which subnet does the host 192.168.19.36/27 belong? - VCEguide.com