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Exhibit

The environment is using BGP All devices are in the same AS with reachability redundancy Referring to the exhibit, which statement is correct?

A.
RR1 is peered to Client2 and RR2
A.
RR1 is peered to Client2 and RR2
Answers
B.
RR2 is in an OpenConfirm State until RR1 becomes unreachable.
B.
RR2 is in an OpenConfirm State until RR1 becomes unreachable.
Answers
C.
Client1 is peered to Client2 and Client3.
C.
Client1 is peered to Client2 and Client3.
Answers
D.
Peering is dynamically discovered between all devices.
D.
Peering is dynamically discovered between all devices.
Answers
Suggested answer: A

Explanation:

BGP route reflectors are BGP routers that are allowed to ignore the IBGP loop avoidance rule and advertise IBGP learned routes to other IBGP peers under specific conditions. BGP route reflectors can reduce the number of IBGP sessions and updates in a network by eliminating the need for a full mesh of IBGP peers. BGP route reflectors can have three types of peerings:

EBGP neighbor: A BGP router that belongs to a different autonomous system (AS) than the route reflector.

IBGP client neighbor: An IBGP router that receives reflected routes from the route reflector. A client does not need to peer with other clients or non-clients.

IBGP non-client neighbor: An IBGP router that does not receive reflected routes from the route reflector. A non-client needs to peer with other non-clients and the route reflector.

In the exhibit, we can see that RR1 and RR2 are route reflectors in the same AS with reachability redundancy. They have two types of peerings: EBGP neighbors (R1 and R4) and IBGP client neighbors (Client1, Client2, and Client3). RR1 and RR2 are also peered with each other as IBGP non-client neighbors.

You are configuring a BGP signaled Layer 2 VPN across your MPLS enabled core network. Your PE-2 device connects to two sites within the s VPN

In this scenario, which statement is correct?

A.
By default on PE-2, the site's local ID is automatically assigned a value of 0 and must be configured to match the total number of attached sites.
A.
By default on PE-2, the site's local ID is automatically assigned a value of 0 and must be configured to match the total number of attached sites.
Answers
B.
You must create a unique Layer 2 VPN routing instance for each site on the PE-2 device.
B.
You must create a unique Layer 2 VPN routing instance for each site on the PE-2 device.
Answers
C.
You must use separate physical interfaces to connect PE-2 to each site.
C.
You must use separate physical interfaces to connect PE-2 to each site.
Answers
D.
By default on PE-2, the remote site IDs are automatically assigned based on the order that you add the interfaces to the site configuration.
D.
By default on PE-2, the remote site IDs are automatically assigned based on the order that you add the interfaces to the site configuration.
Answers
Suggested answer: D

Explanation:

BGP Layer 2 VPNs use BGP to distribute endpoint provisioning information and set up pseudowires between PE devices. BGP uses the Layer 2 VPN (L2VPN) Routing Information Base (RIB) to store endpoint provisioning information, which is updated each time any Layer 2 virtual forwarding instance (VFI) is configured. The prefix and path information is stored in the L2VPN database, which allows BGP to make decisions about the best path.

In BGP Layer 2 VPNs, each site has a unique site ID that identifies it within a VFI. The site ID can be manually configured or automatically assigned by the PE device. By default, the site ID is automatically assigned based on the order that you add the interfaces to the site configuration. The first interface added to a site configuration has a site ID of 1, the second interface added has a site ID of 2, and so on.

Option D is correct because by default on PE-2, the remote site IDs are automatically assigned based on the order that you add the interfaces to the site configuration. Option A is not correct because by default on PE-2, the site's local ID is automatically assigned a value of 0 and does not need to be configured to match the total number of attached sites. Option B is not correct because you do not need to create a unique Layer 2 VPN routing instance for each site on the PE-2 device. You can create one routing instance for all sites within a VFI. Option C is not correct because you do not need to use separate physical interfaces to connect PE-2 to each site. You can use subinterfaces or service instances on a single physical interface.

Exhibit

You must ensure that the VPN backbone is preferred over the back door intra-area link as long as the VPN is available. Referring to the exhibit, which action will accomplish this task?

A.
Configure an import routing policy on the CE routers that rejects OSPF routes learned on the backup intra-area link.
A.
Configure an import routing policy on the CE routers that rejects OSPF routes learned on the backup intra-area link.
Answers
B.
Enable OSPF traffic-engineering.
B.
Enable OSPF traffic-engineering.
Answers
C.
Configure the OSPF metric on the backup intra-area link that is higher than the L3VPN link.
C.
Configure the OSPF metric on the backup intra-area link that is higher than the L3VPN link.
Answers
D.
Create an OSPF sham link between the PE routers.
D.
Create an OSPF sham link between the PE routers.
Answers
Suggested answer: D

Explanation:

A sham link is a logical link between two PE routers that belong to the same OSPF area but are connected through an L3VPN. A sham link makes the PE routers appear as if they are directly connected, and prevents OSPF from preferring an intra-area back door link over the VPN backbone.To create a sham link, you need to configure the local and remote addresses of the PE routers under the [edit protocols ospf area area-id] hierarchy level1.

Exhibit

Which two statements are true about the OSPF adjacency displayed in the exhibit? (Choose two.)

A.
There is a mismatch in the hello interval parameter between routers R1 and R2
A.
There is a mismatch in the hello interval parameter between routers R1 and R2
Answers
B.
There is a mismatch in the dead interval parameter between routers R1 and R2.
B.
There is a mismatch in the dead interval parameter between routers R1 and R2.
Answers
C.
There is a mismatch in the OSPF hold timer parameter between routers R1 and R2.
C.
There is a mismatch in the OSPF hold timer parameter between routers R1 and R2.
Answers
D.
There is a mismatch in the poll interval parameter between routers R1 and R2.
D.
There is a mismatch in the poll interval parameter between routers R1 and R2.
Answers
Suggested answer: A, B

Explanation:

The hello interval is the time interval between two consecutive hello packets sent by an OSPF router on an interface. The dead interval is the time interval after which a neighbor is declared down if no hello packets are received from it. These parameters must match between two OSPF routers for them to form an adjacency. In the exhibit, router R1 has a hello interval of 10 seconds and a dead interval of 40 seconds, while router R2 has a hello interval of 30 seconds and a dead interval of 120 seconds.This causes a mismatch and prevents them from becoming neighbors23.

Exhibit

user@Rl show configuration interpolated-profile { interpolate {

fill-level [ 50 75 drop---probability [ > }

class-of-service drop-profiles

];

20 60 ];

Which two statements are correct about the class-of-service configuration shown in the exhibit? (Choose two.)

A.
The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full.
A.
The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full.
Answers
B.
The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full
B.
The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full
Answers
C.
To use this drop profile, you reference it in a scheduler.
C.
To use this drop profile, you reference it in a scheduler.
Answers
D.
To use this drop profile, you apply it directly to an interface.
D.
To use this drop profile, you apply it directly to an interface.
Answers
Suggested answer: B, C

Explanation:

class-of-service (CoS) is a feature that allows you to prioritize and manage network traffic based on various criteria, such as application type, user group, or packet loss priority. CoS uses different components to classify, mark, queue, schedule, shape, and drop traffic according to the configured policies.

One of the components of CoS is drop profiles, which define how packets are dropped when a queue is congested. Drop profiles use random early detection (RED) algorithm to drop packets randomly before the queue is full, which helps to avoid global synchronization and improve network performance. Drop profiles can be discrete or interpolated. A discrete drop profile maps a specific fill level of a queue to a specific drop probability. An interpolated drop profile maps a range of fill levels of a queue to a range of drop probabilities and interpolates the values in between.

In the exhibit, we can see that the class-of-service configuration shows an interpolated drop profile with two fill levels (50 and 75) and two drop probabilities (20 and 60). Based on this configuration, we can infer the following statements:

The drop probability jumps immediately from 20% to 60% when the queue level reaches 75% full. This is not correct because the drop profile is interpolated, not discrete. This means that the drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full. The drop probability for any fill level between 50% and 75% can be calculated by using linear interpolation formula.

The drop probability gradually increases from 20% to 60% as the queue level increases from 50% full to 75% full. This is correct because the drop profile is interpolated and uses linear interpolation formula to calculate the drop probability for any fill level between 50% and 75%. For example, if the fill level is 60%, the drop probability is 28%, which is calculated by using the formula: (60 - 50) / (75 - 50) * (60 - 20) + 20 = 28.

To use this drop profile, you reference it in a scheduler. This is correct because a scheduler is a component of CoS that determines how packets are dequeued from different queues and transmitted on an interface. A scheduler can reference a drop profile by using the random-detect statement under the [edit class-of-service schedulers] hierarchy level. For example: scheduler test { transmit-rate percent 10; buffer-size percent 10; random-detect test-profile; }

To use this drop profile, you apply it directly to an interface. This is not correct because a drop profile cannot be applied directly to an interface. A drop profile can only be referenced by a scheduler, which can be applied to an interface by using the scheduler-map statement under the [edit class-of-service interfaces] hierarchy level. For example: interfaces ge-0/0/0 { unit 0 { scheduler-map test-map; } }

Which two statements are correct about IS-IS interfaces? (Choose two.)

A.
If a broadcast interface is in both L1 and L2, one combined hello message is sent for both levels.
A.
If a broadcast interface is in both L1 and L2, one combined hello message is sent for both levels.
Answers
B.
If a point-to-point interface is in both L1 and L2, separate hello messages are sent for each level.
B.
If a point-to-point interface is in both L1 and L2, separate hello messages are sent for each level.
Answers
C.
If a point-to-point interface is in both L1 and L2, one combined hello message is sent for both levels.
C.
If a point-to-point interface is in both L1 and L2, one combined hello message is sent for both levels.
Answers
D.
If a broadcast interface is in both L1 and L2, separate hello messages are sent for each level
D.
If a broadcast interface is in both L1 and L2, separate hello messages are sent for each level
Answers
Suggested answer: B, D

Explanation:

IS-IS supports two levels of routing: Level 1 (intra-area) and Level 2 (interarea). An IS-IS router can be either Level 1 only, Level 2 only, or both Level 1 and Level 2. A router that is both Level 1 and Level 2 is called a Level 1-2 router.A Level 1-2 router sends separate hello messages for each level on both point-to-point and broadcast interfaces1. A point-to-point interface provides a connection between a single source and a single destination. A broadcast interface behaves as if the router is connected to a LAN.

A packet is received on an interface configured with transmission scheduling. One of the configured queues In this scenario, which two actions will be taken by default on a Junos device? (Choose two.)

A.
The excess traffic will be discarded
A.
The excess traffic will be discarded
Answers
B.
The exceeding queue will be considered to have negative bandwidth credit.
B.
The exceeding queue will be considered to have negative bandwidth credit.
Answers
C.
The excess traffic will use bandwidth available from other queueses
C.
The excess traffic will use bandwidth available from other queueses
Answers
D.
The exceeding queue will be considered to have positive bandwidth credit
D.
The exceeding queue will be considered to have positive bandwidth credit
Answers
Suggested answer: A, B

Explanation:

https://www.juniper.net/documentation/us/en/software/junos/cos-security-devices/topics/concept/cos-transmission-scheduling-security-overview.html

In IS-IS, which two statements are correct about the designated intermediate system (DIS) on a multi-access network segment? (Choose two)

A.
A router with a priority of 10 wins the DIS election over a router with a priority of 1.
A.
A router with a priority of 10 wins the DIS election over a router with a priority of 1.
Answers
B.
A router with a priority of 1 wins the DIS election over a router with a priority of 10.
B.
A router with a priority of 1 wins the DIS election over a router with a priority of 10.
Answers
C.
On the multi-access network, each router forms an adjacency to every other router on the segment
C.
On the multi-access network, each router forms an adjacency to every other router on the segment
Answers
D.
On the multi-access network, each router only forms an adjacency to the DIS.
D.
On the multi-access network, each router only forms an adjacency to the DIS.
Answers
Suggested answer: A, D

Explanation:

In IS-IS, a designated intermediate system (DIS) is a router that is elected on a multi-access network segment (such as Ethernet) to perform some functions on behalf of other routers on the same segment. A DIS is responsible for sending network link-state advertisements (LSPs), which describe all the routers attached to the network. These LSPs are flooded throughout a single area. A DIS also generates pseudonode LSPs, which represent the multi-access network as a single node in the link-state database. A DIS election is based on the priority value configured on each router's interface connected to the multi-access network. The priority value ranges from 0 to 127, with higher values indicating higher priority. The router with the highest priority becomes the DIS for the area (Level 1, Level 2, or both). If routers have the same priority, then the router with the highest MAC address is elected as the DIS. By default, routers have a priority value of 64. On a multi-access network, each router only forms an adjacency to the DIS, not to every other router on the segment. This reduces the amount of hello packets and LSP

Exhibit

R4 is directly connected to both RPs (R2 and R3) R4 is currently sending all ,o,ns upstream to R3 but you want all joins to go to R2 instead Referring to the exhibit, which configuration change will solve this issue?

A.
Change the bootstrap priority on R2 to be higher than R3
A.
Change the bootstrap priority on R2 to be higher than R3
Answers
B.
Change the default route in inet.2 on R4 from R3 as the next hop to R2
B.
Change the default route in inet.2 on R4 from R3 as the next hop to R2
Answers
C.
Change the local address on R2 to be higher than R3.
C.
Change the local address on R2 to be higher than R3.
Answers
D.
Change the group-range to be more specific on R2 than R3.
D.
Change the group-range to be more specific on R2 than R3.
Answers
Suggested answer: D

In which two ways does OSPF prevent routing loops in multi-area networks? (Choose two.)

A.
All areas are required to connect as a full mesh.
A.
All areas are required to connect as a full mesh.
Answers
B.
The LFA algorithm prunes all looped paths within an area.
B.
The LFA algorithm prunes all looped paths within an area.
Answers
C.
All areas are required to connect to area 0.
C.
All areas are required to connect to area 0.
Answers
D.
The SPF algorithm prunes looped paths within an area.
D.
The SPF algorithm prunes looped paths within an area.
Answers
Suggested answer: C, D

Explanation:

OSPF is an interior gateway protocol that uses link-state routing to exchange routing information among routers within a single autonomous system. OSPF prevents routing loops in multi-area networks by using two methods: area hierarchy and SPF algorithm. Area hierarchy is the concept of dividing a large OSPF network into smaller areas that are connected to a backbone area (area 0). This reduces the amount of routing information that each router has to store and process, and also limits the scope of link-state updates within each area.All areas are required to connect to area 0 either directly or through virtual links2. SPF algorithm is the method that OSPF uses to calculate the shortest path to each destination in the network based on link-state information. The SPF algorithm runs on each router and builds a shortest-path tree that represents the topology of the network from the router's perspective.The SPF algorithm prunes looped paths within an area by choosing only one best path for each destination3.

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