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Question 650 - 220-1102 discussion

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A user with a disability needs to be able to press the Ctrl+Alt+Del keyboard sequence one key at a time. Which of the following turns on this Ease of Access feature?

A.
Press the Shift key five times in a row.
Answers
A.
Press the Shift key five times in a row.
B.
Press Ctrl+Alt+Esc simultaneously.
Answers
B.
Press Ctrl+Alt+Esc simultaneously.
C.
Press Ctrl+Alt+Tab simultaneously.
Answers
C.
Press Ctrl+Alt+Tab simultaneously.
D.
Press the Windows key+Tab.
Answers
D.
Press the Windows key+Tab.
Suggested answer: A

Explanation:

The Ease of Access feature in Windows that allows a user to press keyboard shortcuts one key at a time is called 'Sticky Keys.' Sticky Keys is designed to assist users with disabilities who have difficulty pressing multiple keys simultaneously. To enable Sticky Keys:

Press the Shift key five times in a row: This is the quickest method to activate Sticky Keys. When you press the Shift key five times, a dialog box appears, asking if you want to turn on Sticky Keys. This method is widely documented as the default shortcut for enabling this feature.

Confirmation dialog: A confirmation dialog will appear asking if you want to turn on Sticky Keys. Click 'Yes' to enable it.

Control Panel or Settings: Alternatively, you can enable Sticky Keys through the Control Panel or the Settings app. Go to 'Ease of Access' settings, find the 'Keyboard' section, and turn on Sticky Keys from there.

CompTIA A+ 220-1102 Exam Objectives, Section 1.4: Given a scenario, use the appropriate Microsoft Windows 10 Control Panel utility.

Windows Ease of Access documentation.

asked 02/10/2024
Chuck Crouse
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